Theorem 5p1e6

Description: 5 + 1 = 6. (Contributed by Mario Carneiro, 18-Apr-2015)

	Ref	Expression
Assertion	5p1e6	|- ( 5 + 1 ) = 6

Proof

Step	Hyp	Ref	Expression
1		df-6	|- 6 = ( 5 + 1 )
2	1	eqcomi	|- ( 5 + 1 ) = 6