Metamath Proof Explorer


Theorem anabsi6

Description: Absorption of antecedent into conjunction. (Contributed by NM, 14-Aug-2000)

Ref Expression
Hypothesis anabsi6.1
|- ( ph -> ( ( ps /\ ph ) -> ch ) )
Assertion anabsi6
|- ( ( ph /\ ps ) -> ch )

Proof

Step Hyp Ref Expression
1 anabsi6.1
 |-  ( ph -> ( ( ps /\ ph ) -> ch ) )
2 1 ancomsd
 |-  ( ph -> ( ( ph /\ ps ) -> ch ) )
3 2 anabsi5
 |-  ( ( ph /\ ps ) -> ch )