Metamath Proof Explorer


Theorem anabss1

Description: Absorption of antecedent into conjunction. (Contributed by NM, 20-Jul-1996) (Proof shortened by Wolf Lammen, 31-Dec-2012)

Ref Expression
Hypothesis anabss1.1
|- ( ( ( ph /\ ps ) /\ ph ) -> ch )
Assertion anabss1
|- ( ( ph /\ ps ) -> ch )

Proof

Step Hyp Ref Expression
1 anabss1.1
 |-  ( ( ( ph /\ ps ) /\ ph ) -> ch )
2 1 an32s
 |-  ( ( ( ph /\ ph ) /\ ps ) -> ch )
3 2 anabsan
 |-  ( ( ph /\ ps ) -> ch )