Metamath Proof Explorer


Theorem anasss

Description: Associative law for conjunction applied to antecedent (eliminates syllogism). (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis anasss.1
|- ( ( ( ph /\ ps ) /\ ch ) -> th )
Assertion anasss
|- ( ( ph /\ ( ps /\ ch ) ) -> th )

Proof

Step Hyp Ref Expression
1 anasss.1
 |-  ( ( ( ph /\ ps ) /\ ch ) -> th )
2 1 exp31
 |-  ( ph -> ( ps -> ( ch -> th ) ) )
3 2 imp32
 |-  ( ( ph /\ ( ps /\ ch ) ) -> th )