Metamath Proof Explorer

Theorem animorr

Description: Conjunction implies disjunction with one common formula (2/4). (Contributed by BJ, 4-Oct-2019)

Ref Expression
Assertion animorr 
|- ( ( ph /\ ps ) -> ( ch \/ ps ) )

Proof

Step Hyp Ref Expression
1 simpr 
 |-  ( ( ph /\ ps ) -> ps )
2 1 olcd 
 |-  ( ( ph /\ ps ) -> ( ch \/ ps ) )