Metamath Proof Explorer


Theorem ax8v2

Description: Second of two weakened versions of ax8v , with an extra disjoint variable condition on y , z see comments there. (Contributed by BJ, 7-Dec-2020)

Ref Expression
Assertion ax8v2
|- ( x = y -> ( x e. z -> y e. z ) )

Proof

Step Hyp Ref Expression
1 ax8v
 |-  ( x = y -> ( x e. z -> y e. z ) )