Metamath Proof Explorer


Theorem bj-abf

Description: Shorter proof of abf (which should be kept as abfALT). (Contributed by BJ, 24-Jul-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-abf.1
|- -. ph
Assertion bj-abf
|- { x | ph } = (/)

Proof

Step Hyp Ref Expression
1 bj-abf.1
 |-  -. ph
2 bj-ab0
 |-  ( A. x -. ph -> { x | ph } = (/) )
3 2 1 mpg
 |-  { x | ph } = (/)