Metamath Proof Explorer


Theorem bj-hbs1

Description: Version of hbsb2 with a disjoint variable condition, which does not require ax-13 , and removal of ax-13 from hbs1 . (Contributed by BJ, 23-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-hbs1
|- ( [ y / x ] ph -> A. x [ y / x ] ph )

Proof

Step Hyp Ref Expression
1 sb6
 |-  ( [ y / x ] ph <-> A. x ( x = y -> ph ) )
2 1 biimpri
 |-  ( A. x ( x = y -> ph ) -> [ y / x ] ph )
3 2 axc4i
 |-  ( A. x ( x = y -> ph ) -> A. x [ y / x ] ph )
4 1 3 sylbi
 |-  ( [ y / x ] ph -> A. x [ y / x ] ph )