Metamath Proof Explorer


Theorem breqi

Description: Equality inference for binary relations. (Contributed by NM, 19-Feb-2005)

Ref Expression
Hypothesis breqi.1
|- R = S
Assertion breqi
|- ( A R B <-> A S B )

Proof

Step Hyp Ref Expression
1 breqi.1
 |-  R = S
2 breq
 |-  ( R = S -> ( A R B <-> A S B ) )
3 1 2 ax-mp
 |-  ( A R B <-> A S B )