Metamath Proof Explorer


Theorem cnveqb

Description: Equality theorem for converse. (Contributed by FL, 19-Sep-2011)

Ref Expression
Assertion cnveqb
|- ( ( Rel A /\ Rel B ) -> ( A = B <-> `' A = `' B ) )

Proof

Step Hyp Ref Expression
1 cnvssb
 |-  ( Rel A -> ( A C_ B <-> `' A C_ `' B ) )
2 cnvssb
 |-  ( Rel B -> ( B C_ A <-> `' B C_ `' A ) )
3 1 2 bi2anan9
 |-  ( ( Rel A /\ Rel B ) -> ( ( A C_ B /\ B C_ A ) <-> ( `' A C_ `' B /\ `' B C_ `' A ) ) )
4 eqss
 |-  ( A = B <-> ( A C_ B /\ B C_ A ) )
5 eqss
 |-  ( `' A = `' B <-> ( `' A C_ `' B /\ `' B C_ `' A ) )
6 3 4 5 3bitr4g
 |-  ( ( Rel A /\ Rel B ) -> ( A = B <-> `' A = `' B ) )