Metamath Proof Explorer


Theorem com15

Description: Commutation of antecedents. Swap 1st and 5th. (Contributed by Jeff Hankins, 28-Jun-2009) (Proof shortened by Wolf Lammen, 29-Jul-2012)

Ref Expression
Hypothesis com5.1
|- ( ph -> ( ps -> ( ch -> ( th -> ( ta -> et ) ) ) ) )
Assertion com15
|- ( ta -> ( ps -> ( ch -> ( th -> ( ph -> et ) ) ) ) )

Proof

Step Hyp Ref Expression
1 com5.1
 |-  ( ph -> ( ps -> ( ch -> ( th -> ( ta -> et ) ) ) ) )
2 1 com5l
 |-  ( ps -> ( ch -> ( th -> ( ta -> ( ph -> et ) ) ) ) )
3 2 com4r
 |-  ( ta -> ( ps -> ( ch -> ( th -> ( ph -> et ) ) ) ) )