Metamath Proof Explorer


Definition df-1st

Description: Define a function that extracts the first member, or abscissa, of an ordered pair. Theorem op1st proves that it does this. For example, ( 1st<. 3 , 4 >. ) = 3 . Equivalent to Definition 5.13 (i) of Monk1 p. 52 (compare op1sta and op1stb ). The notation is the same as Monk's. (Contributed by NM, 9-Oct-2004)

Ref Expression
Assertion df-1st
|- 1st = ( x e. _V |-> U. dom { x } )

Detailed syntax breakdown

Step Hyp Ref Expression
0 c1st
 |-  1st
1 vx
 |-  x
2 cvv
 |-  _V
3 1 cv
 |-  x
4 3 csn
 |-  { x }
5 4 cdm
 |-  dom { x }
6 5 cuni
 |-  U. dom { x }
7 1 2 6 cmpt
 |-  ( x e. _V |-> U. dom { x } )
8 0 7 wceq
 |-  1st = ( x e. _V |-> U. dom { x } )