Metamath Proof Explorer


Theorem difeq1i

Description: Inference adding difference to the right in a class equality. (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis difeq1i.1
|- A = B
Assertion difeq1i
|- ( A \ C ) = ( B \ C )

Proof

Step Hyp Ref Expression
1 difeq1i.1
 |-  A = B
2 difeq1
 |-  ( A = B -> ( A \ C ) = ( B \ C ) )
3 1 2 ax-mp
 |-  ( A \ C ) = ( B \ C )