Metamath Proof Explorer


Theorem difeq2i

Description: Inference adding difference to the left in a class equality. (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis difeq1i.1
|- A = B
Assertion difeq2i
|- ( C \ A ) = ( C \ B )

Proof

Step Hyp Ref Expression
1 difeq1i.1
 |-  A = B
2 difeq2
 |-  ( A = B -> ( C \ A ) = ( C \ B ) )
3 1 2 ax-mp
 |-  ( C \ A ) = ( C \ B )