Metamath Proof Explorer


Theorem disjdifg

Description: A class does not intersect a relative complement of a superclass. (Contributed by NM, 24-Mar-1998) Generalize from disjdif . (Revised by BJ, 19-Jul-2026)

Ref Expression
Assertion disjdifg
|- ( A C_ B -> ( A i^i ( C \ B ) ) = (/) )

Proof

Step Hyp Ref Expression
1 ssinss1
 |-  ( A C_ B -> ( A i^i C ) C_ B )
2 inssdif0
 |-  ( ( A i^i C ) C_ B <-> ( A i^i ( C \ B ) ) = (/) )
3 1 2 sylib
 |-  ( A C_ B -> ( A i^i ( C \ B ) ) = (/) )