Metamath Proof Explorer


Theorem dividOLD

Description: Obsolete version of divid as of 9-Jul-2025. (Contributed by NM, 1-Aug-2004) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion dividOLD
|- ( ( A e. CC /\ A =/= 0 ) -> ( A / A ) = 1 )

Proof

Step Hyp Ref Expression
1 divrec
 |-  ( ( A e. CC /\ A e. CC /\ A =/= 0 ) -> ( A / A ) = ( A x. ( 1 / A ) ) )
2 1 3anidm12
 |-  ( ( A e. CC /\ A =/= 0 ) -> ( A / A ) = ( A x. ( 1 / A ) ) )
3 recid
 |-  ( ( A e. CC /\ A =/= 0 ) -> ( A x. ( 1 / A ) ) = 1 )
4 2 3 eqtrd
 |-  ( ( A e. CC /\ A =/= 0 ) -> ( A / A ) = 1 )