Metamath Proof Explorer


Theorem ee010

Description: e010 without virtual deductions. (Contributed by Alan Sare, 23-Jul-2011) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses ee010.1
|- ph
ee010.2
|- ( ps -> ch )
ee010.3
|- th
ee010.4
|- ( ph -> ( ch -> ( th -> ta ) ) )
Assertion ee010
|- ( ps -> ta )

Proof

Step Hyp Ref Expression
1 ee010.1
 |-  ph
2 ee010.2
 |-  ( ps -> ch )
3 ee010.3
 |-  th
4 ee010.4
 |-  ( ph -> ( ch -> ( th -> ta ) ) )
5 1 a1i
 |-  ( ps -> ph )
6 3 a1i
 |-  ( ps -> th )
7 5 2 6 4 syl3c
 |-  ( ps -> ta )