Metamath Proof Explorer
Description: Inference from equality to equivalence of membership. (Contributed by NM, 31-May-1994)
|
|
Ref |
Expression |
|
Hypotheses |
eleq1i.1 |
|- A = B |
|
|
eleq12i.2 |
|- C = D |
|
Assertion |
eleq12i |
|- ( A e. C <-> B e. D ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eleq1i.1 |
|- A = B |
2 |
|
eleq12i.2 |
|- C = D |
3 |
2
|
eleq2i |
|- ( A e. C <-> A e. D ) |
4 |
1
|
eleq1i |
|- ( A e. D <-> B e. D ) |
5 |
3 4
|
bitri |
|- ( A e. C <-> B e. D ) |