Metamath Proof Explorer


Theorem epeli

Description: The membership relation and the membership predicate agree when the "containing" class is a set. Inference associated with epelg . (Contributed by Scott Fenton, 11-Apr-2012)

Ref Expression
Hypothesis epeli.1
|- B e. _V
Assertion epeli
|- ( A _E B <-> A e. B )

Proof

Step Hyp Ref Expression
1 epeli.1
 |-  B e. _V
2 epelg
 |-  ( B e. _V -> ( A _E B <-> A e. B ) )
3 1 2 ax-mp
 |-  ( A _E B <-> A e. B )