Theorem eqimss2i

Description: Infer subclass relationship from equality. (Contributed by NM, 7-Jan-2007)

	Ref	Expression
Hypothesis	eqimssi.1	|- A = B
Assertion	eqimss2i	|- B C_ A

Proof

Step	Hyp	Ref	Expression
1		eqimssi.1	|- A = B
2		ssid	|- B C_ B
3	2 1	sseqtrri	|- B C_ A