Theorem eqimsscd

Description: Equality implies inclusion, deduction version. (Contributed by SN, 15-Feb-2025)

	Ref	Expression
Hypothesis	eqimssd.1	|- ( ph -> A = B )
Assertion	eqimsscd	|- ( ph -> B C_ A )

Proof

Step	Hyp	Ref	Expression
1		eqimssd.1	|- ( ph -> A = B )
2		ssid	|- A C_ A
3	1 2	eqsstrrdi	|- ( ph -> B C_ A )