Theorem eqimssd

Description: Equality implies inclusion, deduction version. (Contributed by SN, 6-Nov-2024)

	Ref	Expression
Hypothesis	eqimssd.1	|- ( ph -> A = B )
Assertion	eqimssd	|- ( ph -> A C_ B )

Proof

Step	Hyp	Ref	Expression
1		eqimssd.1	|- ( ph -> A = B )
2		ssid	|- B C_ B
3	1 2	eqsstrdi	|- ( ph -> A C_ B )