Theorem eqimssi

Description: Infer subclass relationship from equality. (Contributed by NM, 6-Jan-2007)

	Ref	Expression
Hypothesis	eqimssi.1	|- A = B
Assertion	eqimssi	|- A C_ B

Proof

Step	Hyp	Ref	Expression
1		eqimssi.1	|- A = B
2		ssid	|- A C_ A
3	2 1	sseqtri	|- A C_ B