Metamath Proof Explorer


Theorem eqtr2

Description: A transitive law for class equality. (Contributed by NM, 20-May-2005) (Proof shortened by Andrew Salmon, 25-May-2011) (Proof shortened by Wolf Lammen, 24-Oct-2024)

Ref Expression
Assertion eqtr2
|- ( ( A = B /\ A = C ) -> B = C )

Proof

Step Hyp Ref Expression
1 eqeq1
 |-  ( A = B -> ( A = C <-> B = C ) )
2 1 biimpa
 |-  ( ( A = B /\ A = C ) -> B = C )