Metamath Proof Explorer


Theorem eqtrid

Description: An equality transitivity deduction. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypotheses eqtrid.1
|- A = B
eqtrid.2
|- ( ph -> B = C )
Assertion eqtrid
|- ( ph -> A = C )

Proof

Step Hyp Ref Expression
1 eqtrid.1
 |-  A = B
2 eqtrid.2
 |-  ( ph -> B = C )
3 1 a1i
 |-  ( ph -> A = B )
4 3 2 eqtrd
 |-  ( ph -> A = C )