Metamath Proof Explorer


Theorem equsexv

Description: An equivalence related to implicit substitution. Version of equsex with a disjoint variable condition, which does not require ax-13 . See equsexvw for a version with two disjoint variable conditions requiring fewer axioms. See also the dual form equsalv . (Contributed by NM, 5-Aug-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses equsalv.nf
|- F/ x ps
equsalv.1
|- ( x = y -> ( ph <-> ps ) )
Assertion equsexv
|- ( E. x ( x = y /\ ph ) <-> ps )

Proof

Step Hyp Ref Expression
1 equsalv.nf
 |-  F/ x ps
2 equsalv.1
 |-  ( x = y -> ( ph <-> ps ) )
3 sbalex
 |-  ( E. x ( x = y /\ ph ) <-> A. x ( x = y -> ph ) )
4 1 2 equsalv
 |-  ( A. x ( x = y -> ph ) <-> ps )
5 3 4 bitri
 |-  ( E. x ( x = y /\ ph ) <-> ps )