Metamath Proof Explorer


Theorem exp31

Description: An exportation inference. (Contributed by NM, 26-Apr-1994)

Ref Expression
Hypothesis exp31.1
|- ( ( ( ph /\ ps ) /\ ch ) -> th )
Assertion exp31
|- ( ph -> ( ps -> ( ch -> th ) ) )

Proof

Step Hyp Ref Expression
1 exp31.1
 |-  ( ( ( ph /\ ps ) /\ ch ) -> th )
2 1 ex
 |-  ( ( ph /\ ps ) -> ( ch -> th ) )
3 2 ex
 |-  ( ph -> ( ps -> ( ch -> th ) ) )