Metamath Proof Explorer


Theorem exp32

Description: An exportation inference. (Contributed by NM, 26-Apr-1994)

Ref Expression
Hypothesis exp32.1
|- ( ( ph /\ ( ps /\ ch ) ) -> th )
Assertion exp32
|- ( ph -> ( ps -> ( ch -> th ) ) )

Proof

Step Hyp Ref Expression
1 exp32.1
 |-  ( ( ph /\ ( ps /\ ch ) ) -> th )
2 1 ex
 |-  ( ph -> ( ( ps /\ ch ) -> th ) )
3 2 expd
 |-  ( ph -> ( ps -> ( ch -> th ) ) )