Theorem exp4c

Description: An exportation inference. (Contributed by NM, 26-Apr-1994)

	Ref	Expression
Hypothesis	exp4c.1	|- ( ph -> ( ( ( ps /\ ch ) /\ th ) -> ta ) )
Assertion	exp4c	|- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )

Proof

Step	Hyp	Ref	Expression
1		exp4c.1	|- ( ph -> ( ( ( ps /\ ch ) /\ th ) -> ta ) )
2	1	expd	|- ( ph -> ( ( ps /\ ch ) -> ( th -> ta ) ) )
3	2	expd	|- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )