Metamath Proof Explorer


Theorem expdimp

Description: A deduction version of exportation, followed by importation. (Contributed by NM, 6-Sep-2008)

Ref Expression
Hypothesis expdimp.1
|- ( ph -> ( ( ps /\ ch ) -> th ) )
Assertion expdimp
|- ( ( ph /\ ps ) -> ( ch -> th ) )

Proof

Step Hyp Ref Expression
1 expdimp.1
 |-  ( ph -> ( ( ps /\ ch ) -> th ) )
2 1 expd
 |-  ( ph -> ( ps -> ( ch -> th ) ) )
3 2 imp
 |-  ( ( ph /\ ps ) -> ( ch -> th ) )