Theorem expimpd

Description: Exportation followed by a deduction version of importation. (Contributed by NM, 6-Sep-2008)

	Ref	Expression
Hypothesis	expimpd.1	|- ( ( ph /\ ps ) -> ( ch -> th ) )
Assertion	expimpd	|- ( ph -> ( ( ps /\ ch ) -> th ) )

Proof

Step	Hyp	Ref	Expression
1		expimpd.1	|- ( ( ph /\ ps ) -> ( ch -> th ) )
2	1	ex	|- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	impd	|- ( ph -> ( ( ps /\ ch ) -> th ) )