Metamath Proof Explorer

Theorem expr

Description: Export a wff from a right conjunct. (Contributed by Jeff Hankins, 30-Aug-2009)

Ref Expression
Hypothesis expr.1 
|- ( ( ph /\ ( ps /\ ch ) ) -> th )
Assertion expr 
|- ( ( ph /\ ps ) -> ( ch -> th ) )

Proof

Step Hyp Ref Expression
1 expr.1 
 |-  ( ( ph /\ ( ps /\ ch ) ) -> th )
2 1 exp32 
 |-  ( ph -> ( ps -> ( ch -> th ) ) )
3 2 imp 
 |-  ( ( ph /\ ps ) -> ( ch -> th ) )