Metamath Proof Explorer


Theorem feq3

Description: Equality theorem for functions. (Contributed by NM, 1-Aug-1994)

Ref Expression
Assertion feq3
|- ( A = B -> ( F : C --> A <-> F : C --> B ) )

Proof

Step Hyp Ref Expression
1 sseq2
 |-  ( A = B -> ( ran F C_ A <-> ran F C_ B ) )
2 1 anbi2d
 |-  ( A = B -> ( ( F Fn C /\ ran F C_ A ) <-> ( F Fn C /\ ran F C_ B ) ) )
3 df-f
 |-  ( F : C --> A <-> ( F Fn C /\ ran F C_ A ) )
4 df-f
 |-  ( F : C --> B <-> ( F Fn C /\ ran F C_ B ) )
5 2 3 4 3bitr4g
 |-  ( A = B -> ( F : C --> A <-> F : C --> B ) )