Metamath Proof Explorer


Theorem fnimadisj

Description: A class that is disjoint with the domain of a function has an empty image under the function. (Contributed by FL, 24-Jan-2007)

Ref Expression
Assertion fnimadisj
|- ( ( F Fn A /\ ( A i^i C ) = (/) ) -> ( F " C ) = (/) )

Proof

Step Hyp Ref Expression
1 fndm
 |-  ( F Fn A -> dom F = A )
2 1 ineq1d
 |-  ( F Fn A -> ( dom F i^i C ) = ( A i^i C ) )
3 2 eqeq1d
 |-  ( F Fn A -> ( ( dom F i^i C ) = (/) <-> ( A i^i C ) = (/) ) )
4 3 biimpar
 |-  ( ( F Fn A /\ ( A i^i C ) = (/) ) -> ( dom F i^i C ) = (/) )
5 imadisj
 |-  ( ( F " C ) = (/) <-> ( dom F i^i C ) = (/) )
6 4 5 sylibr
 |-  ( ( F Fn A /\ ( A i^i C ) = (/) ) -> ( F " C ) = (/) )