Metamath Proof Explorer


Theorem freq12d

Description: Equality deduction for well-founded relations. (Contributed by Stefan O'Rear, 19-Jan-2015) (Proof shortened by Matthew House, 10-Sep-2025)

Ref Expression
Hypotheses freq12d.1
|- ( ph -> R = S )
freq12d.2
|- ( ph -> A = B )
Assertion freq12d
|- ( ph -> ( R Fr A <-> S Fr B ) )

Proof

Step Hyp Ref Expression
1 freq12d.1
 |-  ( ph -> R = S )
2 freq12d.2
 |-  ( ph -> A = B )
3 freq1
 |-  ( R = S -> ( R Fr A <-> S Fr A ) )
4 freq2
 |-  ( A = B -> ( S Fr A <-> S Fr B ) )
5 3 4 sylan9bb
 |-  ( ( R = S /\ A = B ) -> ( R Fr A <-> S Fr B ) )
6 1 2 5 syl2anc
 |-  ( ph -> ( R Fr A <-> S Fr B ) )