Theorem funeqi

Description: Equality inference for the function predicate. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

	Ref	Expression
Hypothesis	funeqi.1	|- A = B
Assertion	funeqi	|- ( Fun A <-> Fun B )

Proof

Step	Hyp	Ref	Expression
1		funeqi.1	|- A = B
2		funeq	|- ( A = B -> ( Fun A <-> Fun B ) )
3	1 2	ax-mp	|- ( Fun A <-> Fun B )