Theorem fveq1d

Description: Equality deduction for function value. (Contributed by NM, 2-Sep-2003)

	Ref	Expression
Hypothesis	fveq1d.1	|- ( ph -> F = G )
Assertion	fveq1d	|- ( ph -> ( F ` A ) = ( G ` A ) )

Proof

Step	Hyp	Ref	Expression
1		fveq1d.1	|- ( ph -> F = G )
2		fveq1	|- ( F = G -> ( F ` A ) = ( G ` A ) )
3	1 2	syl	|- ( ph -> ( F ` A ) = ( G ` A ) )