Description: Define the biconditional as conditional logic operator. (Contributed by RP, 20-Apr-2020) (Proof shortened by Wolf Lammen, 30-Apr-2024)
Ref | Expression | ||
---|---|---|---|
Assertion | ifpdfbi | |- ( ( ph <-> ps ) <-> if- ( ph , ps , -. ps ) ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | con34b | |- ( ( ps -> ph ) <-> ( -. ph -> -. ps ) ) |
|
2 | 1 | anbi2i | |- ( ( ( ph -> ps ) /\ ( ps -> ph ) ) <-> ( ( ph -> ps ) /\ ( -. ph -> -. ps ) ) ) |
3 | dfbi2 | |- ( ( ph <-> ps ) <-> ( ( ph -> ps ) /\ ( ps -> ph ) ) ) |
|
4 | dfifp2 | |- ( if- ( ph , ps , -. ps ) <-> ( ( ph -> ps ) /\ ( -. ph -> -. ps ) ) ) |
|
5 | 2 3 4 | 3bitr4i | |- ( ( ph <-> ps ) <-> if- ( ph , ps , -. ps ) ) |