Theorem imdistanda

Description: Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011)

	Ref	Expression
Hypothesis	imdistanda.1	|- ( ( ph /\ ps ) -> ( ch -> th ) )
Assertion	imdistanda	|- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

Proof

Step	Hyp	Ref	Expression
1		imdistanda.1	|- ( ( ph /\ ps ) -> ( ch -> th ) )
2	1	ex	|- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	imdistand	|- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )