Metamath Proof Explorer


Theorem imdistani

Description: Distribution of implication with conjunction. (Contributed by NM, 1-Aug-1994)

Ref Expression
Hypothesis imdistani.1
|- ( ph -> ( ps -> ch ) )
Assertion imdistani
|- ( ( ph /\ ps ) -> ( ph /\ ch ) )

Proof

Step Hyp Ref Expression
1 imdistani.1
 |-  ( ph -> ( ps -> ch ) )
2 1 anc2li
 |-  ( ph -> ( ps -> ( ph /\ ch ) ) )
3 2 imp
 |-  ( ( ph /\ ps ) -> ( ph /\ ch ) )