Metamath Proof Explorer


Theorem ineq1i

Description: Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993)

Ref Expression
Hypothesis ineq1i.1
|- A = B
Assertion ineq1i
|- ( A i^i C ) = ( B i^i C )

Proof

Step Hyp Ref Expression
1 ineq1i.1
 |-  A = B
2 ineq1
 |-  ( A = B -> ( A i^i C ) = ( B i^i C ) )
3 1 2 ax-mp
 |-  ( A i^i C ) = ( B i^i C )