Database
SUPPLEMENTARY MATERIAL (USERS' MATHBOXES)
Mathbox for Jarvin Udandy
mdandyvrx4
Metamath Proof Explorer
Description: Given the exclusivities set in the hypotheses, there exist a proof where
ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin
Udandy , 7-Sep-2016)
Ref
Expression
Hypotheses
mdandyvrx4.1
|- ( ph \/_ ze )
mdandyvrx4.2
|- ( ps \/_ si )
mdandyvrx4.3
|- ( ch <-> ph )
mdandyvrx4.4
|- ( th <-> ph )
mdandyvrx4.5
|- ( ta <-> ps )
mdandyvrx4.6
|- ( et <-> ph )
Assertion
mdandyvrx4
|- ( ( ( ( ch \/_ ze ) /\ ( th \/_ ze ) ) /\ ( ta \/_ si ) ) /\ ( et \/_ ze ) )
Proof
Step
Hyp
Ref
Expression
1
mdandyvrx4.1
|- ( ph \/_ ze )
2
mdandyvrx4.2
|- ( ps \/_ si )
3
mdandyvrx4.3
|- ( ch <-> ph )
4
mdandyvrx4.4
|- ( th <-> ph )
5
mdandyvrx4.5
|- ( ta <-> ps )
6
mdandyvrx4.6
|- ( et <-> ph )
7
1 3
axorbciffatcxorb
|- ( ch \/_ ze )
8
1 4
axorbciffatcxorb
|- ( th \/_ ze )
9
7 8
pm3.2i
|- ( ( ch \/_ ze ) /\ ( th \/_ ze ) )
10
2 5
axorbciffatcxorb
|- ( ta \/_ si )
11
9 10
pm3.2i
|- ( ( ( ch \/_ ze ) /\ ( th \/_ ze ) ) /\ ( ta \/_ si ) )
12
1 6
axorbciffatcxorb
|- ( et \/_ ze )
13
11 12
pm3.2i
|- ( ( ( ( ch \/_ ze ) /\ ( th \/_ ze ) ) /\ ( ta \/_ si ) ) /\ ( et \/_ ze ) )