Metamath Proof Explorer


Theorem mon1pn0

Description: Monic polynomials are not zero. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses uc1pn0.p
|- P = ( Poly1 ` R )
uc1pn0.z
|- .0. = ( 0g ` P )
mon1pn0.m
|- M = ( Monic1p ` R )
Assertion mon1pn0
|- ( F e. M -> F =/= .0. )

Proof

Step Hyp Ref Expression
1 uc1pn0.p
 |-  P = ( Poly1 ` R )
2 uc1pn0.z
 |-  .0. = ( 0g ` P )
3 mon1pn0.m
 |-  M = ( Monic1p ` R )
4 eqid
 |-  ( Base ` P ) = ( Base ` P )
5 eqid
 |-  ( deg1 ` R ) = ( deg1 ` R )
6 eqid
 |-  ( 1r ` R ) = ( 1r ` R )
7 1 4 2 5 3 6 ismon1p
 |-  ( F e. M <-> ( F e. ( Base ` P ) /\ F =/= .0. /\ ( ( coe1 ` F ) ` ( ( deg1 ` R ) ` F ) ) = ( 1r ` R ) ) )
8 7 simp2bi
 |-  ( F e. M -> F =/= .0. )