Metamath Proof Explorer
		
		
		
		Description:  Substitution of equal classes into an inequality.  (Contributed by NM, 4-Jul-2012)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | neeqtrrd.1 | |- ( ph -> A =/= B ) | 
					
						|  |  | neeqtrrd.2 | |- ( ph -> C = B ) | 
				
					|  | Assertion | neeqtrrd | |- ( ph -> A =/= C ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | neeqtrrd.1 |  |-  ( ph -> A =/= B ) | 
						
							| 2 |  | neeqtrrd.2 |  |-  ( ph -> C = B ) | 
						
							| 3 | 2 | eqcomd |  |-  ( ph -> B = C ) | 
						
							| 4 | 1 3 | neeqtrd |  |-  ( ph -> A =/= C ) |