Metamath Proof Explorer


Theorem negned

Description: If two complex numbers are unequal, so are their negatives. Contrapositive of neg11d . (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses negidd.1
|- ( ph -> A e. CC )
negned.2
|- ( ph -> B e. CC )
negned.3
|- ( ph -> A =/= B )
Assertion negned
|- ( ph -> -u A =/= -u B )

Proof

Step Hyp Ref Expression
1 negidd.1
 |-  ( ph -> A e. CC )
2 negned.2
 |-  ( ph -> B e. CC )
3 negned.3
 |-  ( ph -> A =/= B )
4 1 2 neg11ad
 |-  ( ph -> ( -u A = -u B <-> A = B ) )
5 4 necon3bid
 |-  ( ph -> ( -u A =/= -u B <-> A =/= B ) )
6 3 5 mpbird
 |-  ( ph -> -u A =/= -u B )