Metamath Proof Explorer


Theorem negsubi

Description: Relationship between subtraction and negative. Theorem I.3 of Apostol p. 18. (Contributed by NM, 26-Nov-1994) (Proof shortened by Andrew Salmon, 22-Oct-2011)

Ref Expression
Hypotheses negidi.1
|- A e. CC
pncan3i.2
|- B e. CC
Assertion negsubi
|- ( A + -u B ) = ( A - B )

Proof

Step Hyp Ref Expression
1 negidi.1
 |-  A e. CC
2 pncan3i.2
 |-  B e. CC
3 negsub
 |-  ( ( A e. CC /\ B e. CC ) -> ( A + -u B ) = ( A - B ) )
4 1 2 3 mp2an
 |-  ( A + -u B ) = ( A - B )