Metamath Proof Explorer


Theorem negsval2d

Description: Surreal negation in terms of subtraction. (Contributed by Scott Fenton, 15-Apr-2025)

Ref Expression
Hypothesis negsval2d.1
|- ( ph -> A e. No )
Assertion negsval2d
|- ( ph -> ( -us ` A ) = ( 0s -s A ) )

Proof

Step Hyp Ref Expression
1 negsval2d.1
 |-  ( ph -> A e. No )
2 negsval2
 |-  ( A e. No -> ( -us ` A ) = ( 0s -s A ) )
3 1 2 syl
 |-  ( ph -> ( -us ` A ) = ( 0s -s A ) )