Metamath Proof Explorer

Theorem neqcomd

Description: Commute an inequality. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypothesis neqcomd.1 
|- ( ph -> -. A = B )
Assertion neqcomd 
|- ( ph -> -. B = A )

Proof

Step Hyp Ref Expression
1 neqcomd.1 
 |-  ( ph -> -. A = B )
2 eqcom 
 |-  ( A = B <-> B = A )
3 1 2 sylnib 
 |-  ( ph -> -. B = A )