Metamath Proof Explorer


Theorem nfci

Description: Deduce that a class A does not have x free in it. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nfci.1
|- F/ x y e. A
Assertion nfci
|- F/_ x A

Proof

Step Hyp Ref Expression
1 nfci.1
 |-  F/ x y e. A
2 df-nfc
 |-  ( F/_ x A <-> A. y F/ x y e. A )
3 2 1 mpgbir
 |-  F/_ x A