Metamath Proof Explorer


Theorem nfsb4

Description: A variable not free in a proposition remains so after substitution in that proposition with a distinct variable. Usage of this theorem is discouraged because it depends on ax-13 . Theorem nfsb replaces the distinctor with a disjoint variable condition. Visit also nfsbv for a weaker version of nfsb not requiring ax-13 . (Contributed by NM, 14-May-1993) (Revised by Mario Carneiro, 4-Oct-2016) (New usage is discouraged.)

Ref Expression
Hypothesis nfsb4.1
|- F/ z ph
Assertion nfsb4
|- ( -. A. z z = y -> F/ z [ y / x ] ph )

Proof

Step Hyp Ref Expression
1 nfsb4.1
 |-  F/ z ph
2 nfsb4t
 |-  ( A. x F/ z ph -> ( -. A. z z = y -> F/ z [ y / x ] ph ) )
3 2 1 mpg
 |-  ( -. A. z z = y -> F/ z [ y / x ] ph )